Final answer:
The reaction between iron(II) carbonate and hydroiodic acid produces iron(II) iodide, carbon dioxide, and water, represented by the balanced chemical equation: FeCO3(s) + 2HI(aq) → FeI2(aq) + CO2(g) + H2O(l).
Step-by-step explanation:
The chemical reaction between iron(II) carbonate and hydroiodic acid can be represented by a balanced chemical equation. When these two reactants come into contact, iron(II) carbonate reacts with hydroiodic acid to form iron(II) iodide, carbon dioxide, and water. The balanced chemical equation for this reaction is:
FeCO3(s) + 2HI(aq) → FeI2(aq) + CO2(g) + H2O(l)
The reaction involves the iron(II) carbonate solid reacting with the hydroiodic acid in an aqueous solution, leading to the products mentioned above. To balance this equation, ensure that the number of atoms for each element is equal on both sides of the equation. Here, you have one iron (Fe) atom, one carbon (C) atom, and three oxygen (O) atoms from the iron(II) carbonate, along with two hydrogen (H) atoms and two iodine (I) atoms from the hydroiodic acid. This yields one iron atom in the iron(II) iodide, two iodine atoms, one carbon atom in the carbon dioxide, and two hydrogen atoms bonded to one oxygen atom to form water, bringing the equation into balance.