Question

If Luis pulls straight down on the end of a wrench that is tilted θ = 30° above the horizontal and is r = 29 cm long, what force must he apply to exert a torque of -17 N⋅m ?

Answer 1

Luis must apply a force of approximately 116.55 N to exert a torque of -17 N·m on a wrench that is 29 cm long and tilted at a 30° angle.

Step-by-step explanation:

To calculate the force that Luis must apply to exert a torque of -17 N·m on a wrench that is tilted θ = 30° above the horizontal, and with a length r = 29 cm (0.29 m), we can use the formula for torque, T = rF sin θ, where T is torque, r is the distance from the pivot point to the point where the force is applied, F is the magnitude of the force, and θ is the angle between the force and the lever arm.

First, we rearrange the formula to solve for F: F = T / (r sin θ). Substituting the given values: F = 17 N·m / (0.29 m × sin(30°)) = 17 N·m / (0.29 m × 0.5) = 116.55 N approximately. Therefore, Luis must apply a force of roughly 116.55 N to achieve the desired torque.