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Find the linearization l(x) of the function at a. f(x) = cos(x), a = π/2

a) l(x) = -sin(π/2)(x - π/2) + cos(π/2)
b) l(x) = sin(π/2)(x - π/2) + cos(π/2)
c) l(x) = cos(π/2)(x - π/2) + sin(π/2)
d) l(x) = -cos(π/2)(x - π/2) + sin(π/2)

User Citrullin
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1 Answer

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Final answer:

The linearization of the cosine function at π/2 is -x + π/2. The correct answer is d) l(x) = -cos(π/2)(x - π/2) + sin(π/2).

Step-by-step explanation:

Linearization refers to the process of approximating a nonlinear function by a linear function at a particular point. In essence, it involves creating a linear equation that closely represents the behavior of a function near a specific point on the curve.

The linearization of a function at a point a is given by the equation:

l(x) = f(a) + f'(a)(x - a)

In this case, the function is f(x) = cos(x) and the point is a = π/2. To find the linearization, we need to find the value of f(a) and f'(a).

Since f(a) = cos(π/2) = 0 and f'(a) = -sin(π/2) = -1, the linearization is:

l(x) = 0 - 1(x - π/2) = -x + π/2

User TanmayP
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