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What torque value do you use when installing the nut of the bolt that passes through the ACES II drogue gun slug?

User Doan
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1 Answer

5 votes

Final answer:

Torque exerted on a bolt by a force of 165 N at a distance of 0.140 m from the center is 23.1 N.m, which converts to 17.05 ft.lb using the conversion factor of 1 N.m = 0.73756 ft.lb.

Step-by-step explanation:

The torque applied to a bolt when you push perpendicularly on a wrench with a force of 165 N at a distance of 0.140 m from the center of the bolt is calculated using the torque formula torque = force x distance. To get the torque in newton-meters, simply multiply the force by the distance from the bolt's center:

torque = 165 N x 0.140 m = 23.1 N.m.

To convert this torque from newton-meters to foot-pounds, you use the conversion factor that 1 N.m equals approximately 0.73756 foot-pounds. Accordingly:

torque in foot-pounds = 23.1 N.m x 0.73756 = 17.05 ft.lb.

User Marcus Lind
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