Answer:
The type of bond that forms between sulfur (S) and fluorine (F) is a polar covalent bond.
Explanation:
The electronegativity values for sulfur (S) and fluorine (F) are:
Sulfur (S): Electronegativity around 2.58
Fluorine (F): Electronegativity around 3.98
The greater the difference in electronegativity between two atoms, the more likely it is that an ionic or polar covalent bond will form.
In this case, the electronegativity difference between fluorine and sulfur is significant (3.98 - 2.58 = 1.4), indicating a polar covalent bond. Fluorine is more electronegative than sulfur, so it will attract the shared electrons more strongly.