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Show that [a+x]ⁿ=aⁿ[1+×/a]ⁿ, a≠0
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Oct 2, 2022
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Show that
[a+x]ⁿ=aⁿ[1+×/a]ⁿ, a≠0
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Lajja Thaker
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Oct 8, 2022
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