Final answer:
One mole of water is produced for every mole of acetic acid that reacts with sodium hydroxide according to the balanced chemical equation CH3COOH + NaOH → CH3COONa + H2O.
Step-by-step explanation:
The reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH) is a neutralization reaction represented by the following balanced chemical equation:
CH3COOH + NaOH → CH3COONa + H2O
According to the equation, the mole ratio of acetic acid to water is 1:1. Therefore, for every mole of acetic acid that reacts, one mole of water is produced.
So, the correct answer to the question, "How many moles of water are produced by the reaction between acetic acid and sodium hydroxide?" is (a) 1 mol.