Final answer:
To find the frequency range for a singer with a 2.5-octave range, we take the lower boundary of their range and multiply it by 2 to the power of 2.5. The provided options do not directly match the calculation, suggesting an error or the need for additional context regarding the singer's range starting point.
Step-by-step explanation:
An opera singer with a 2.5-octave range would have a frequency range that depends on their starting frequency.
An octave represents a doubling or halving of a frequency. So, to calculate the frequency range, we would take the starting frequency and multiply it by 2 to the power of 2.5 (since an octave is a doubling of frequency).
Let's assume the lowest frequency the singer can reach is 120 Hz. Therefore, to find the high end of their range we calculate:
120 Hz × 22.5 = 120 Hz × 5.66 ≈ 680 Hz.
This range isn't listed among the provided options, which suggests the need for considering different starting frequencies. If we consider a starting frequency of 240 Hz, then:
240 Hz × 22.5 = 240 Hz × 5.66 ≈ 1360 Hz.
Among the given options, option b, which is 240 Hz to 960 Hz, is the closest to our calculation. However, a precise range should ideally align with one of the specific options provided, indicating the need for further clarification.