Question

Hydriodic acid (aq) and potassium sulfite (aq) net ionic equation.

a) 2HI(aq) + K₂SO₃(aq) → 2Kl(aq) + H₂O(l) + SO₂(g)
b) 2H⁺(aq) + 2I⁻(aq) + K⁺(aq) + SO₃²⁻(aq) → 2K⁺(aq) + 2I⁻(aq) + H₂O(l) + SO₂(g)
c) 2HI(aq) + K₂SO₃(aq) → 2K⁺(aq) + 2I⁻(aq) + SO₂(g) + H₂O(l)
d) 2H⁺(aq) + SO₃²⁻(aq) → SO₂(g) + H₂O(l)

Answer 1

The net ionic equation for the reaction between hydriodic acid (HI) and potassium sulfite (K₂SO₃) is 2H⁺(aq) + SO₃²⁻(aq) → SO₂(g) + H₂O(l), which shows the hydrogen ions reacting with sulfite ions to form sulfur dioxide and water.

Step-by-step explanation:

The student is asking for the net ionic equation for the reaction between hydriodic acid (HI) and potassium sulfite (K₂SO₃). In such reactions, spectator ions (ions that do not participate in the reaction) are omitted to show the actual chemical change taking place.

The balanced molecular equation for the reaction is:
2HI(aq) + K₂SO₃(aq) → 2KI(aq) + H₂O(l) + SO₂(g)

To find the net ionic equation, we remove the spectator ions, in this case, the potassium ions (K⁺). The remaining ions are the ones that participate in the chemical reaction. Therefore, the net ionic equation is:
2H⁺(aq) + SO₃²⁻(aq) → SO₂(g) + H₂O(l)