Final answer:
To find the number of nitrogen atoms in 1.2 grams of aspartame, we calculate the number of moles of aspartame and multiply by Avogadro's number and the number of nitrogen atoms per molecule. The result is approximately 4.91 × 10²± atoms, which does not match any of the provided options.
Step-by-step explanation:
The student's question is about calculating the number of atoms of nitrogen in 1.2 grams of aspartame. Aspartame has a molecular formula of C14H18N2O5, which means it contains 2 atoms of nitrogen per molecule. First, we need to determine the molar mass of aspartame. Using the atomic weights of carbon, hydrogen, nitrogen, and oxygen, the molar mass is approximately 294 g/mol (14*12 + 18*1 + 2*14 + 5*16 = 294). Next, to find the number of moles of aspartame in 1.2 grams, we use the formula: Moles = mass (in grams) / molar mass. Therefore, we have 1.2 g / 294 g/mol = 0.00408 mol of aspartame.
Since there are 2 atoms of nitrogen in one molecule of aspartame, we can then calculate the total number of nitrogen atoms by multiplying the number of moles of aspartame by Avogadro's number (6.022 × 10²³ atoms/mol) and then by 2 (since there are 2 nitrogen atoms per molecule of aspartame): 0.00408 mol × 6.022 × 10²³ atoms/mol × 2 ≈ 4.91 × 10²± atoms of nitrogen. This result is not listed in the options, suggesting there might be a typo in the question or answer choices. Therefore, without the correct options, it is not possible to select one of the given answers (a, b, c, d).