Final answer:
The photon energy of light with a wavelength of 615 nm is approximately 3.23 x 10^-19 J.
Step-by-step explanation:
The energy of a photon can be calculated using the formula:
E = hf
where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency. To find the energy of a photon with a given wavelength, we need to use the relationship between frequency and wavelength of light:
c = λf
where c is the speed of light (3.00 x 10^8 m/s), λ is the wavelength, and f is the frequency.
Using this relationship, we can calculate the frequency and then use it to find the energy of the photon.
Given that the wavelength of light is 615 nm, we can convert it to meters by multiplying by 10^-9:
λ = 615 nm = 615 x 10^-9 m
Now we can rearrange the equation to solve for frequency:
f = c/λ
Substituting the values:
f = (3.00 x 10^8 m/s)/(615 x 10^-9 m) = 4.88 x 10^14 Hz
Finally, we can use the calculated frequency to find the energy:
E = hf = (6.626 x 10^-34 J·s) x (4.88 x 10^14 Hz) = 3.23 x 10^-19 J
Therefore, the photon energy of light with a wavelength of 615 nm is 3.23 x 10^-19 J.