Question

(x+y)³ Expand the Binomial. ​

Answer 1

Answer: (x+y)³=x³+3x²y+3xy²+y³

Explanation:

`\displaystyle\\(x+y)^3=\\\\C^0_3x^3y^0+C_3^1x^2y^1+C_3^2x^1y^2+C_3^3x^0y^3=\\\\(3!)/((3-0)!0!) x^31+(3!)/((3-1)!1!) x^2y+(3!)/((3-2)!2!) xy^2+(3!)/((3-3)!3!) 1y^3=\\\\(3!)/(3!1) x^3+(2!3)/(2!) x^2y+(2!3)/(1!2!) xy^2+(3!)/(0!3!)y^3=\\\\x^3+3x^2y+3xy^2+y^3`