Question

Which nutrient protects blood cells, body tissue, and essential fatty acids from destruction in the body? It is found in fortified multigrain cereals, nuts, wheat germ, vegetable oils, and green leafy vegetables.

1) Potassium
2) Vitamin B12
3) Vitamin E
4) Calcium

Answer 1

Vitamin E is the nutrient that protects blood cells, body tissue, and essential fatty acids from destruction in the body. It acts as an antioxidant and can be found in various food sources. It is important for the functioning of enzymes and overall health.

Step-by-step explanation:

Vitamin E is the nutrient that protects blood cells, body tissue, and essential fatty acids from destruction in the body. It can be found in fortified multigrain cereals, nuts, wheat germ, vegetable oils, and green leafy vegetables. Vitamin E acts as an antioxidant, scavenging harmful by-products of metabolism and preventing fats from becoming rancid. It is important for the functioning of certain enzymes and plays a role in maintaining good health.

Answer 2

Vitamin E is the nutrient that protects blood cells, body tissue, and essential fatty acids and is found in multigrain cereals, nuts, wheat germ, vegetable oils, and green vegetables.

Step-by-step explanation:

The nutrient that protects blood cells, body tissue, and essential fatty acids from destruction in the body is Vitamin E. It is an antioxidant that helps protect cells from damage by free radicals. Foods high in Vitamin E include fortified multigrain cereals, nuts, wheat germ, vegetable oils, and green leafy vegetables. This vitamin, unlike vitamins B and C which are water-soluble, is fat-soluble, meaning it can be stored in body fat. An excess of Vitamin E can build up to unhealthy levels in your cells if consumed in large amounts over time.