2 \sin(x) - √(3) = 0 when(\pi)/(2) \leqslant x \leqslant \pi

Question

asked Mar 1, 2022 52.3k views

1 Answer

Osdamv · Answer 1 · 2022-03-07T02:08:20+0000

Given:

The equation is

$2\sin x-√(3)=0$

When
$(\pi)/(2)\leq x\leq \pi$ .

To find:

The value of x.

Solution:

We have,

$2\sin x-√(3)=0$

It can be written as

$2\sin x=√(3)$

$\sin x=(√(3))/(2)$

It is given that
$(\pi)/(2)\leq x\leq \pi$ .

$\sin x=\sin \left(\pi-(\pi)/(3)\right)$

$x=(3\pi-\pi)/(3)$

$x=(2\pi)/(3)$

Therefore, the value of x is
$(2\pi)/(3)$ .