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How to simplify cos(π/7) * cos(x) * sin(π/7) * sin(x)?

a) sin(2x - π/7)
b) cos(2x + π/7)
c) sin(2x + π/7)
d) cos(2x - π/7)

User NgLover
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1 Answer

4 votes

Final answer:

To simplify the expression cos(π/7) * cos(x) * sin(π/7) * sin(x), we can apply the trigonometric identity sin(a) * cos(b) = (1/2) * [sin(a + b) + sin(a - b)]. Expanding and simplifying the expression leads to option d) cos(2x - π/7).

Step-by-step explanation:

To simplify the expression cos(π/7) * cos(x) * sin(π/7) * sin(x), we can use the trigonometric identity sin(a) * cos(b) = (1/2) * [sin(a + b) + sin(a - b)].

Applying this identity twice, we have:

cos(π/7) * cos(x) * sin(π/7) * sin(x) = (1/2) * [sin(π/7 + x) + sin(π/7 - x)] * (1/2) * [sin(π/7 + x) - sin(π/7 - x)]

Expanding and simplifying further, we get:

cos(π/7) * cos(x) * sin(π/7) * sin(x) = (1/4) * [sin(2x + π/7) - sin(π/7 - 2x)]

Therefore, the simplified form of the expression is option d) cos(2x - π/7).

User Nick Soper
by
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