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This 800 kg dragster gets up to 100 miles per hour from rest in 0.8 s.

a. What is the change in momentum of the dragster? (4 pt)
b. What is the average force exerted on the dragster? (4 pt)
c. What exerts that force? (2 pt)

User Jalalala
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1 Answer

14 votes
14 votes

Answer:

here,

the mass of car , m = 800 kg

the initial speed of car , u = 100 mph

u = 44.7 m/s

time taken , t = 0.8 s

a)

the change in momentum of the car , dP = Pf - Pi

dP = m * 0 - m * u

dP = - 800 * 44.7 kg.m/s

dP = - 3.58 * 10^4 kg.m/s

b)

the average force exerted on the car , F = dP /t

F = - 3.58 * 10^4 /(0.8) N

F = - 4.47 * 10^4 N

c)

this force is exerted by road on the car

User April Smith
by
2.7k points