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Simplify Cos(a+b) +Cos(a+b)​

User Bradrice
by
6.5k points

1 Answer

3 votes
At the risk of piling on after correct answers have already been given, I’ll offer another way to address this problem. Recall that, if
θ
is real, cos()=Re()
cos

(
θ
)
=
R
e
(
e
i
θ
)
. So, with
A
and
B
real,

(+)+(−)=(+−)=2cos()
e
i
(
A
+
B
)
+
e
i
(
A

B
)
=
e
i
A
(
e
i
B
+
e

i
B
)
=
2
e
i
A
cos

(
B
)

Finally,

cos(+)+cos(−)=Re((+)+(−))=Re(2cos())
cos

(
A
+
B
)
+
cos

(
A

B
)
=
R
e
(
e
i
(
A
+
B
)
+
e
i
(
A

B
)
)
=
R
e
(
2
e
i
A
cos

(
B
)
)

=2cos()cos()
User Whiskeyo
by
6.9k points