Question

Solve the equation 2x² - 6x + 8=0 using the quadratic formula

a) x = -2, 4
b) x = 2, -4
c) x = -1, 4
d) x = 1, -4

Answer 1

To solve the equation 2x² - 6x + 8=0 using the quadratic formula, we can substitute the values of a, b, and c into the formula and simplify to find the solutions. However, in this case, the equation has no real solutions.

Step-by-step explanation:

To solve the equation 2x² - 6x + 8 = 0 using the quadratic formula, we can identify the values of a, b, and c as follows:

a = 2, b = -6, c = 8

Then, we can substitute these values into the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values, we get:

x = (-(-6) ± √((-6)² - 4(2)(8))) / (2(2))

Simplifying further:

x = (6 ± √(36 - 64)) / 4

x = (6 ± √(-28)) / 4

The square root of a negative number is not defined in the set of real numbers. Hence, there are no real solutions to the given equation.