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The pro shop at the hidden oaks country club ordered two brands of golf balls. Lightning balls cost $2.10 each and the Par one balls cost $0.90 each. The total cost of lightning balls exceeded the total cost of the par one balls by $360.00. If an equal number of each brand was ordered, how many dozens of each brand were ordered

User Danny
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Final answer:

The pro shop at Hidden Oaks Country Club ordered 25 dozens of each brand of golf balls, with the cost of Lightning balls being $2.10 each and Par one balls at $0.90 each, and a total cost difference of $360.

Step-by-step explanation:

The question deals with finding the number of dozens of golf balls ordered based on the given costs for each brand of golf balls and the total cost difference.

To begin solving the problem, let's denote the number of golf balls ordered for each brand as 'x'. The cost of Lightning balls is $2.10 each, and the cost of Par one balls is $0.90 each. We're given that the total cost for Lightning balls exceeds that of Par one balls by $360.

The equations we can derive from the information given are as follows:

  • Cost of Lightning balls: $2.10 × x
  • Cost of Par one balls: $0.90 × x
  • Difference in cost: ($2.10 × x) \u2212 ($0.90 × x) = $360

Combining these, we get:

$2.10x - $0.90x = $360
$1.20x = $360
x = $360 / $1.20
x = 300

Since x represents the total number of balls, we need to convert this into dozens (where 1 dozen equals 12 balls). Thus:

300 balls ÷ 12 balls/dozen = 25 dozens

Therefore, the pro shop ordered 25 dozens of each brand of golf balls.

User Kayo
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