147k views
4 votes
Find the x-intercepts of f(x) = x² - 4x - 5

a) x = -1, x = 5
b) x = -5, x = 1
c) x = -1, x = -5
d) x = 1, x = 5

1 Answer

4 votes

Final answer:

The x-intercepts of the quadratic function f(x) = x² - 4x - 5 are x = 5 and x = -1. The correct answer is a) x = -1, x = 5.

Step-by-step explanation:

To find the x-intercepts of the quadratic function f(x) = x² - 4x - 5, we need to set the equation equal to zero and solve for x.

Step 1: Set f(x) = 0:

x² - 4x - 5 = 0

Step 2: Factor the quadratic equation or use the quadratic formula to solve for x.

In this case, the factors of the quadratic equation are (x - 5)(x + 1) = 0.

Setting each factor equal to zero:

x - 5 = 0 or x + 1 = 0

Solving for x:

x = 5 or x = -1

Therefore, the x-intercepts of f(x) = x² - 4x - 5 are x = 5 and x = -1.

User Mediafreakch
by
7.8k points