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Y+1/4x=1x=−1/4x+1 how many solutions

(THE 1/4 ARE FRACTIONS BTW)

User Vatsal
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The system of equations has one unique solution, which is (x, y) = (1, 1).

This problem involves solving a system of equations with two variables, y and x. The equations given are:


\(y + (1)/(4)x = 1\)


\(x = -(1)/(4)y + 1\)

To determine the number of solutions, let's examine the equations. The second equation is already solved for x in terms of y, so we can substitute this expression for x into the first equation:


\(y + (1)/(4)x = 1\)

Substitute
\(x = -(1)/(4)y + 1\):


\(y + (1)/(4) \cdot (-(1)/(4)y + 1) = 1\)

Simplify the equation:


\(y - (1)/(16)y + (1)/(4) = 1\)

Combine like terms:


\((15)/(16)y + (1)/(4) = 1\)

Now, isolate y:


\((15)/(16)y = 1 - (1)/(4)\)


\((15)/(16)y = (3)/(4)\)


\(y = (3)/(4) * (16)/(15)\)


\(y = 1\)

Now that we have found y, let's substitute it back into the second equation to find x:


\(x = -(1)/(4)y + 1\)


\(x = -(1)/(4) * 1 + 1\)


\(x = 1\)

After solving, we find that y = 1 and x = 1. Both equations are satisfied when x = 1 and y = 1. Therefore, the system of equations has one unique solution, which is (x, y) = (1, 1).

User Flogy
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