138k views
4 votes
Find the solutions to the system: {y=x²-9x+12, y=3x+4}

a) (-3, -3)
b) (-2, 2)
c) (4, 16)
d) (5, 19)

User BlackCath
by
8.1k points

1 Answer

3 votes

Final answer:

To find the solutions to the system of equations {y=x²-9x+12, y=3x+4}, we can set the two equations equal to each other and solve for x. Using the quadratic formula, we find that x=4 and x=2 are the solutions. Substituting these values back into either equation, we find the corresponding y-values.

Step-by-step explanation:

To find the solutions to the system of equations {y=x²-9x+12, y=3x+4}, we can set the two equations equal to each other and solve for x.

x²-9x+12 = 3x+4

Combining like terms and rearranging the equation, we get:

x²-12x+8 = 0

We can then use the quadratic formula to solve this equation:

x = (-b ± √(b²-4ac))/(2a)

where a = 1, b = -12, and c = 8. Plugging in the values, we get two solutions: x = 4 and x = 2. Substituting these values back into either of the original equations, we can find the corresponding y-values:

When x = 4, y = 3(4) + 4 = 16+4 = 20. So, one solution is (4, 20).

When x = 2, y = 3(2) + 4 = 6+4 = 10. So, another solution is (2, 10).

User Bronzato
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.