Question

What values of x between 0 and

2π satisfy the equation sin(x)−1=0? A. x= π/2
B. x=π
C. x=3π/2
D. No solution within the range

Answer 1

The solution to sin(x)-1=0 between 0 and 2π is x=π/2, which is option A. This is because sin(π/2) equals 1, satisfying the equation sin(x)=1.

Step-by-step explanation:

The equation given is sin(x)-1=0. To find the values of x that satisfy this equation between 0 and 2π, we can solve for x as follows:

• sin(x) = 1

Considering the unit circle and the values of the sine function, the sine of an angle is equal to 1 at x=π/2 (90 degrees).

Therefore, the solution to the equation within the given range is A. x=π/2.