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What is the value of 2θ, given sin θ = -√3/5 and cos θ > 0?

a) 4π/3
b) 5π/3
c) 2π/3
d) π/3

User Heals
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1 Answer

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Final answer:

To find the value of 2θ, use the given information of sin θ and cos θ. Use the trigonometric identity sin^2 θ + cos^2 θ = 1 to solve for cos θ. Then use the double-angle formula for cosine to find the value of 2θ.

Step-by-step explanation:

To find the value of 2θ, we need to use the given information of sin θ and cos θ. We know that sin θ = -√3/5 and cos θ > 0. We can use the trigonometric identity sin^2 θ + cos^2 θ = 1 to find cos θ. Since sin θ = -√3/5, we can substitute this value into the equation and solve for cos θ.

sin^2 θ + cos^2 θ = 1

((-√3/5)^2) + cos^2 θ = 1

3/5 + cos^2 θ = 1

cos^2 θ = 1 - 3/5

cos^2 θ = 2/5

cos θ = √(2/5)

Since cos θ > 0, cos θ = √(2/5)

We can now find the value of 2θ by using the double-angle formula for cosine: cos(2θ) = 2cos^2 θ - 1

cos(2θ) = 2(√(2/5))^2 - 1

cos(2θ) = 2(2/5) - 1

cos(2θ) = 4/5 - 1

cos(2θ) = -1/5

Since cos(2θ) = -1/5, we can find the value of 2θ by taking the inverse cosine of -1/5: 2θ = cos^(-1)(-1/5)

The decimal value of 2θ is approximately -78.46°.

User Elevener
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