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Sketch the graph of 9x²+16y² = 144 and locate the foci?

User NMunro
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1 Answer

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The foci are located as points A and B on the graph of the ellipse.

What is an ellipse?

Given 9x² + 16y² = 144.

This represents an ellipse equation.

To sketch the graph, we first rewrite the equation in standard form:

x²/(4/3)² + y²/3²= 1

This gives the semi-major axis a = 3 and the semi-minor axis b = 4/3.

The foci F of an ellipse are given by

c = √a² - b²

c = √3² - (4/3)²

c = √9 - 16/9

c =√65/9

c = √7.222

c = +-2.7

The foci will be on the major axis, so they will be along the x-axis.

The foci are located as points A and B on the graph of the ellipse.

Sketch the graph of 9x²+16y² = 144 and locate the foci?-example-1
User AmirAli Saghaei
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8.4k points