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Sin(arccot(x)) algebraic expression
a) sin(x)
b) cos(x)
c) tan(x)
d) cot(x)

User Dsounded
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7.6k points

1 Answer

4 votes

Final answer:

Sin(arccot(x)) can be determined by considering a right triangle where cot(theta) = x. The algebraic expression is sin(arccot(x)) = 1/√(1 + x^2), which is not one of the provided options, but rather involves a square root.

Step-by-step explanation:

To find the algebraic expression for sin(arccot(x)), we must express the sine function in terms of a known trigonometric function of x. The cotangent function is the reciprocal of the tangent function. Thus, if we consider a right triangle where cot(θ) = x, meaning the adjacent side over the opposite side, we can define the sides of the triangle based on x.

In the context of a right triangle with an angle θ, we can let the adjacent side (to θ) be x and the opposite side be 1 (since cot(θ) = adjacent/opposite). Using the Pythagorean theorem, the hypotenuse would be √(1^2 + x^2).

Therefore, sin(θ), which is the opposite over the hypotenuse, can be expressed as:

sin(θ) = 1/√(1 + x^2)

This simplifies to the algebraic expression:

sin(arccot(x)) = 1/√(1 + x^2)

None of the options a) sin(x), b) cos(x), c) tan(x), d) cot(x) is correct. The expression involves a square root and is not simply one of the basic trigonometric functions.

User Annonymous
by
7.9k points
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