34.0k views
3 votes
How do you write an equation of a line passing through (-4, -3), perpendicular to 4x + y=7?

1 Answer

2 votes

Final answer:

To find the equation of a line perpendicular to another line, determine the slope of the original line and take its negative reciprocal. Using the point-slope form of a line and the given point, substitute the values to find the equation.

Step-by-step explanation:

To find the equation of a line perpendicular to another line, we first need to determine the slope of the original line. The given equation of the line is 4x + y = 7. We can rewrite it in slope-intercept form as y = -4x + 7. The slope of the original line is -4. The slope of a line perpendicular to it is the negative reciprocal of -4, which is 1/4. Using the point (-4, -3) and the slope 1/4, we can use the point-slope form of a line to find the equation of the perpendicular line:



y - y1 = m(x - x1)



Substituting (-4, -3) for (x1, y1) and 1/4 for m, we get:



y - (-3) = 1/4(x - (-4))



Simplifying the equation, we have:



y + 3 = 1/4(x + 4)



This is the equation of the line passing through (-4, -3) and perpendicular to 4x + y = 7.

User Vlmercado
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories