Question

Sixteen liters of an ideal gas at a temperature of 500 kelvin has a pressure of 100 newtons per square meter. If the

volume were increased to 20 liters and the temperature reduced to 400 kelvin, what would be the pressure?

Answer 1

Answer: Pressure = 16 neutons per sq. meter

Explanation:

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Volume = k[t/p]

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Find "k":

16 = k[500/100]

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k = 16/5

V = (16/5)[t/p]

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If the volume were increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure?

20 = (16/5)[400/p]

pressure = (16/5)[500/20]