HELP MEEEEEEEEEEEEEEEEEEEEE PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Webblover asked Jun 14, 2023

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16 votes

Webblover asked Jun 14, 2023

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10 votes

Part a

Setting
x=6 ,
$y=7.9(1.02)^6 \approx \boxed{8.9}$

Part b

Setting
x=14 ,
$y=7.9(1.02)^(14) \approx \boxed{10.4}$

Glitches answered Jun 20, 2023

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