Question

A 75 kg box is being pulled across a horizontal floor by a force acting upwards at a 53° angle from above the horizon. What is the magnitude of the applied force if the box is moving at a constant speed? (The coefficient of friction is 0.2)

Answer 1

The magnitude of the applied force is 147 N.

Step-by-step explanation:

To find the magnitude of the applied force, we need to consider the forces acting on the box. The force exerted upwards at a 53° angle is counteracted by the weight of the box acting downwards.

The weight can be calculated using the formula: weight = mass * gravity, where gravity is approximately 9.8 m/s².

The force of friction can be calculated using the formula: frictional force = coefficient of friction * normal force, where the normal force is equal to the weight of the box since it is on a horizontal floor.

Since the box is moving at a constant speed, the applied force must be equal to the force of friction. So, we can use the formula: applied force = frictional force.

Plugging in the values, we have:
Weight = 75 kg * 9.8 m/s²

= 735 N

Frictional force = 0.2 * 735 N

= 147 N
Therefore, the magnitude of the applied force is 147 N.