Question

I need help asap
I will need help finding a and b

Answer 1

(a)
`s = 2.56`

(b)
`s = 1.71`

Explanation:

Given

Tables (a) and (b)

Required

Determine the standard deviation

For (a):

`\bar x = 11.5` --- mean

The standard deviation is calculated as:

`s = √(\sum np(1-p))`

This gives:

`s = √(5*0.1*(1-0.1) +10 * 0.5 * (1 - 0.5) + 15 *0.4*(1-0.4) )`

`s = √(5*0.1*0.9 +10 * 0.5 * 0.5 + 15 *0.4*0.6 )`

`s = √(6.55)`

`s = 2.56`

For (b):

`\bar x = 4.4` --- mean

The standard deviation is calculated as:

`s = √(\sum np(1-p))`

This gives:

`s = √(1*0.2*(1-0.2) +3 * 0.3 * (1 - 0.3) + 5 *0.1*(1-0.1) + 7*0.4*(1-0.4))`

`s = √(1*0.2*0.8 +3 * 0.3 * 0.7 + 5 *0.1*0.9 + 7*0.4*0.6)`

`s = √(2.92)`

`s = 1.71`