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What is the equation of a line parallel to y = 3x - 1 that passes through the point (-2, 3)?

a) y = 3x - 9
b) y = 3x + 9
c) y = 3x - 3
d) y = 3x + 3

1 Answer

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Final answer:

The equation of a line parallel to y = 3x - 1 that passes through the point (-2, 3) is y = 3x + 9. The equation of a line parallel to y = 3x - 1 that passes through the point (-2, 3) is y = 3x + 9 (option b).

Step-by-step explanation:

The equation of a line parallel to y = 3x - 1 will also have a slope of 3 because parallel lines have the same slope. We can use the point-slope form of a line to find the equation. The point-slope form is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

Given that the line passes through the point (-2, 3) and has a slope of 3, we can substitute these values into the point-slope form:

y - 3 = 3(x - (-2))

Simplifying the equation, we get y - 3 = 3x + 6.

Therefore, the equation of a line parallel to y = 3x - 1 that passes through the point (-2, 3) is y = 3x + 9 (option b).

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