Answer:
The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³
Step-by-step explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
pOH indicates the concentration of hydroxyl ions [OH-] present in a solution. In this way, pOH is defined as the negative logarithm of the activity of hydroxide ions, that is, the concentration of OH- ions:
pOH= -log [OH⁻]
In this case, pOH has a value of 2.7. Replacing:
2.7= -log [OH⁻]
and solving:
[OH⁻]=10⁻² ⁷
you get:
[OH⁻]≅ 2*10⁻³
The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³