Question

What is the concentration of [ h+ ] in solution given the [ oh- ] = 2.45x10^-4

Answer 1

Given
`\([OH^-] = 2.45 * 10^(-4)\)`, the concentration of hydrogen ions
`\([H^+]\)` is approximately
`\(4.08 * 10^(-11)\)` based on the ion product constant of water.

To find the concentration of hydrogen ions
`\([H^+]\)` in a solution when the hydroxide ion concentration
`\([OH^-]\)` is given, we can use the ion product constant of water
`(\(K_w\))`. For a neutral solution at 25°C,
`\(K_w\)` is
`\(1.0 * 10^(-14)\)`, which is the product of
`\([H^+]\)` and
`\([OH^-]\)`.

`\[ K_w = [H^+] * [OH^-] \]`

Given that
`\([OH^-] = 2.45 * 10^(-4)\)`, substitute this into the equation:

`\[ 1.0 * 10^(-14) = [H^+] * (2.45 * 10^(-4)) \]`

Now, solve for
`\([H^+]\)`:

`\[ [H^+] = (1.0 * 10^(-14))/(2.45 * 10^(-4)) \]`

`\[ [H^+] \approx 4.08 * 10^(-11) \]`

Therefore, the concentration of hydrogen ions
`\([H^+]\)` in the solution is approximately
`\(4.08 * 10^(-11)\)`.