Question

Part A

Using opposite operations, rewrite the equation so s2 is on one side of the equation by itself.


Part B
What is the opposite operation of squaring? Using this opposite operation, rewrite the equation from question 1 so s is by itself on one side of the equation.



Part C
The pyramid of Khufu, also known as the Great Pyramid of Giza, is one of the Seven Wonders of the World. Its volume is about 2,433,400 cubic meters, and its height is about 138 meters. Substitute these values into the equation from Part B, and solve the equation.



Part D
Search the Internet to find the length of each side of the base of Khufu’s pyramid. Does this length match your calculation?

Part E
Khafre was a son of Khufu. He also had a pyramid built, but it was not as big as his father’s. The volume of the Pyramid of Khafre is about 2,115,072 cubic meters, and its height is about 136 meters. Approximate the length of each side of the base?

Part F
Search the Internet to find the length of each side of the base of Khafre’s pyramid. Does this match your calculation?

Part G
About how much longer are the side lengths of the base of Khufu’s pyramid than Khafre’s?

Answer 1

Part A: S^2= 3V/H

Part B: S =
`\sqrt{3(v)/(h) }`

Part C: s=√3* 2,433,400 /138=230 metres

Part D: This website says that the length of Khufu's Pyramid is about 230 meters. My calculation was correct.

Part E: S = √3*2,115,072/ 136 =216 metres

Part F: The length of Khafre's pyramid is about 215.5 My calculation was a little off, but not by much.

Part G: 14 meters longer

Explanation:

Part A:

I am going to solve:

So,

V=1/3
`HS^(2)`

Then, multiply both sides by 3:

V x 3= 1/3
`HS^(2)` x 3

So,

3V=
`HS^(2)`

Then, we divide by H:

`(3V)/(H)`=
`(HSs^(2) )/(H)`

So,

`(3V)/(H)`=
`s^(2)`

Then switch sides:

`s^(2)`=
`(3V)/(H)`

I hope this helps!