Question

[urgent]

What would the [OH-] of a solution that has a pOH of 2.7 be?

Answer 1

[OH⁻] = 0.002 M

Step-by-step explanation:

The definition of pOH is similar to the definition of pH:

• pOH = -log[OH⁻]

This means that with a given pOH value, the calculation of [OH⁻] is a matter of algebra:

• 2.7 = -log[OH⁻]

• -2.7 = log[OH⁻]

To remove the logarithm we increase 10 by the power of the pOH:

• 
  `10^(-2.7)`=[OH⁻]

• 0.002 M = [OH⁻]