Question

A chip is burned beneath an aluminum container holding 28.7 g of water causing the temperature of the water to increase from 11.3 °C to 33.2 °C. How many joules of heat were absorbed by the water? Water’s specific heat is 4.18 J/gºC

Answer 1

Q = 2627.25 J

Step-by-step explanation:

Given that,

The mass of water, m = 28.7 g

The temperature of the water to increase from 11.3 °C to 33.2 °C

The specific heat of water is 4.18 J/gºC

The heat absorbed by the water is given by :

`Q=mc\Delta T\\\\Q=28.7 * 4.18 * (33.2-11.3)\\\\Q=2627.25\ J`

So, 2627.25 J of heat is absorbed by the water.