Final answer:
Andre picked 240 apples. This was determined by establishing a variable for the number of apples Maria picked, creating expressions for the apples picked by Andre and Jane based on the given relationships, and solving the resulting equation.
Step-by-step explanation:
The student's question is: How many apples did Andre pick if Jane, Andre, and Maria picked 840 apples in total, where Andre picks two times as much as Maria and Jane picks twice as much as Andre?
Let's denote the number of apples Maria picked as M. It's given that Andre picks two times as much as Maria, so Andre picked 2M apples. Furthermore, Jane picks twice as much as Andre, which means Jane picked 2(2M) = 4M apples. Since the total number of apples picked is 840, we can write the following equation:
M + 2M + 4M = 840
Adding the terms on the left side gives us 7M = 840. Dividing both sides by 7 to solve for M:
M = 840 / 7M = 120
Since M (the number of apples Maria picked) is 120, we can determine that Andre picked 2 × 120 = 240 apples.
In this question, we are given that Jane, Andre, and Maria pick 840 apples. We are also given that Andre picks two times as much as Maria, and Jane picks twice as much as Andre.
Let's assume that Maria picks x apples. Since Andre picks two times as much as Maria, Andre picks 2x apples. And since Jane picks twice as much as Andre, Jane picks 2 * 2x = 4x apples.
Now, we can set up an equation to represent the total number of apples picked: x + 2x + 4x = 840. Simplifying this equation, we get 7x = 840. Dividing both sides by 7, we find that x = 120.
Therefore, Andre picked 2 * 120 = 240 apples