Final answer:
To prepare 100 cm³ of a 0.01 M NaOH solution, you would need 1 mL of a 1 M NaOH stock solution.
Step-by-step explanation:
To calculate the volume (v1) of NaOH required to make 100 cm³ (which is equivalent to 0.1 L) of a 0.01 M NaOH solution, we use the formula c1⋅v1 = c2⋅v2 where c1 and v1 are the concentration and volume of the stock solution, and c2 and v2 are the desired concentration and volume of the final solution. First, we need to calculate the moles of NaOH needed using the formula moles = molarity × volume. Thus, moles of NaOH = 0.01 M × 0.1 L = 0.001 moles of NaOH.
Assuming we have a stock solution that is 1 M NaOH (which means 1 mol/L), we can calculate the volume of this stock solution that contains 0.001 moles of NaOH using the formula:
v1 = moles / concentration of stock = 0.001 moles / 1 M = 0.001 L of NaOH
To convert liters to milliliters, we multiply by 1000, which gives us:
v1 = 0.001 L × 1000 mL/L = 1 mL
Therefore, the volume (v1) of a 1 M NaOH stock solution needed to prepare 100 cm³ of a 0.01 M NaOH solution is 1 mL.