Final answer:
The discussed computer network question involves calculating the number of server stalls and total latency with n links, relating to dynamic congestion windows for a given payload size b, segment size s, total round-trip time (rtt), and link speed (r).
Step-by-step explanation:
The question asked relates to network communications and the concept of dynamic congestion windows in the context of n links separating a sender and receiver. To answer this question, one would need to calculate the number of server stalls and the total latency for transmitting an object of b bytes split into segments of s bytes. Total latency would include the sum of transmission delays for each segment, propagated over n links, while also considering the total round-trip time (rtt) and the link speed (r bytes/second).
The number of server stalls would correspond to the number of times the sender must wait before receiving acknowledgment (ACK) for all segments, assuming dynamic adjustments of the congestion window size. Each stall corresponds to waiting for an rtt. Total latency includes initial rtt, the transmission time for all segments (which is b/s times for sending each s byte segment over r bytes/second speed), and any additional stalls multiplied by the rtt.
Considering each of these elements, one could derive an expression involving n, rtt, b, s, and r to represent the total latency and the number of server stalls.