Final answer:
A stack-oriented processor involves push and pop operations to manipulate elements in a stack. This processor automatically pushes the output on top of the stack. After executing the given instructions, the final stack elements remaining are 5.
Step-by-step explanation:
In a stack-oriented processor, the push operation adds an element to the top of the stack, while the pop operation removes the top element from the stack. In this case, we start with an empty stack.
Let's go through the instructions:
- push(3) - This adds the number 3 to the top of the stack. The stack now contains: 3
- pop() - This removes the top element from the stack. The stack is now empty.
- push(5) - This adds the number 5 to the top of the stack. The stack now contains: 5
- push(2) - This adds the number 2 to the top of the stack. The stack now contains: 5, 2
- pop() - This removes the top element from the stack. The stack now contains: 5
- push(8) - This adds the number 8 to the top of the stack. The stack now contains: 5, 8
- pop() - This removes the top element from the stack. The stack now contains: 5
So, after executing all the instructions, the final stack elements remaining are: 5.