Question

What would the scan time be in a 2D FSE sequence utilizing TR = 4000 ms, 2 signal averages, 288 phase encoding lines of matrix with an echo train of 12?

Answer 1

The scan time for a 2D Fast Spin Echo sequence with TR = 4000 ms, 2 signal averages, 288 phase encoding lines, and an echo train of 12 is 96 seconds.

Step-by-step explanation:

The scan time for a 2D FSE (Fast Spin Echo) sequence can be calculated using the formula: Scan Time = TR x Phase Encoding Steps x Signal Averages x Echo Train Length. Given TR (Repetition Time) = 4000 ms, 2 signal averages, 288 phase encoding lines, and an echo train of 12, the scan time would be:

Scan Time = 4000 ms x 288 x 2 x 1/12
= 4000 ms x 24
= 96,000 ms
= 96 seconds

Therefore, the scan time would be 96 seconds. The scan time in a 2D FSE sequence can be calculated using the formula:

Scan Time = TR x Signal Averages x Phase Encoding Lines.