Question

to Raise money for new football uniforms or school is selling short sleeve and long sleeve T-shirts short sleeve shirts cost five dollars to make and sell for eight dollars each long sleeve shirts cost seven dollars and sell for $12 each school spent a total of 2500 and sold all the items for $4200 how

Answer 1

The number of short-sleeved shirts ordered (x) is 150, and the number of long-sleeved shirts ordered (y) is 100.

Let's solve the system of equations to find the values of x (number of short-sleeved shirts) and y (number of long-sleeved shirts).

The system of equations is:

5x+10y=1,750

1/3 x+ 1/2 y=100

We can start by multiplying the second equation by 6 to eliminate fractions:

5x+10y=1,750

2x+3y=600 (Multiply each term in the second equation by 6)

Now we can use the substitution or elimination method to solve the system. I'll use the substitution method.

From equation (2), solve for x:

2x+3y=600

2x=600−3y

x=300− 3/2 y

Now substitute this expression for x into equation (1):

5(300− 3/2 y)+10y=1,750

Simplify the equation:

1,500− 15 /2 y+10y=1,750

Combine like terms:

5/2 y=250

Now solve for y:

y=100

Now substitute the value of y back into the expression we found for x:

x=300− 3/2 (100)

x=300−150

x=150

Therefore, the number of short-sleeved shirts ordered (x) is 150, and the number of long-sleeved shirts ordered (y) is 100.