Final answer:
To find a two-digit number that is a multiple of 5 and has three fewer tens than ones, the ones digit must be 5, making the tens digit 2, resulting in the number 25.
Step-by-step explanation:
The question is asking us to find a two-digit number that meets two criteria: 1) the number is a multiple of 5, and 2) the tens digit is three less than the ones digit. To be a multiple of 5, our number must end in either a 0 or a 5.
Since we need the tens digit to be three less than the ones digit, ending in 0 would not work because we cannot have a negative digit.
Therefore, the number must end in 5. Now the tens digit must be three less than the ones digit.
Since the ones digit is 5, the tens digit must be 2 (5 - 3 = 2). So, the number that fits these criteria is 25.