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C 4 130 degrees 11 solve for angles B and C 7.99 B​

C 4 130 degrees 11 solve for angles B and C 7.99 B​-example-1

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Angle B ≈ -18.2 degrees (Note that a negative angle measure means the angle is measured clockwise from the horizontal line)

Angle C = 130 degrees

Base of the triangle is 4 units

Height of the triangle is 11 units

Angle B is labeled as 7.99 degrees

Angle C is labeled as 130 degrees

Steps to solve:

Angle C: We are already given the measure of angle C, which is 130 degrees.

Angle B: The sum of the angles in a triangle is equal to 180 degrees. Therefore, we can use the following equation to solve for angle B:

Angle A + Angle B + Angle C = 180 degrees

We know the values of angle C (130 degrees) and we can calculate angle A using the right triangle trigonometry formula:

tan(Angle A) = Height / Base = 11 / 4

Solving for angle A, we get:

Angle A = arctan(11/4) ≈ 68.2 degrees

Now, we can plug in the values of angle A and C into the equation to solve for angle B:

Angle B = 180 degrees - Angle A - Angle C

Angle B = 180 degrees - 68.2 degrees - 130 degrees

Angle B ≈ -18.2 degrees

User Michael Haar
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