Question

Jax created a puzzle using their age and their mom Vera's age. Vera is 11 years older than twice Jax's age. Vera is also 15 years less than quadruple Jax's age. Use substitution to figure out both Jax’s & Vera's ages.

Answer 1

Jax's age is 13 years old and Vera's age is 37 years old.

Step-by-step explanation:

To solve this problem, we can use substitution to represent Jax's age and Vera's age in terms of Jax's age. Let's say Jax's age is represented by 'x'.

According to the given information, Vera is 11 years older than twice Jax's age. So, Vera's age can be represented as '2x + 11'.

Vera is also 15 years less than quadruple Jax's age, which can be written as '4x - 15'.

Now we can set up an equation using these representations.

2x + 11 = 4x - 15

Solving this equation, we subtract 2x from both sides:

11 = 2x - 15

Adding 15 to both sides:

26 = 2x

Dividing both sides by 2:

x = 13

Therefore, Jax's age is 13 years old. To find Vera's age, we can substitute this value back into one of the earlier representations of Vera's age.

Using '2x + 11', we get:

Vera's age = 2(13) + 11

= 26 + 11

= 37

Therefore, Jax's age is 13 years old and Vera's age is 37 years old.