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Select the equation below that has solutions of 1-3i and 1+3i *
(1 Point)
O A. O = x2 – 2x - 10
O B. 0 = x2 -- 2x + 10
O C. O = x2 – 2x + 8
O D. 0 = x2 - 2x - 8
PLS HELP!!!

User Lykos
by
6.7k points

1 Answer

5 votes

Answer:


x^2 - 2x + 10, option B

Explanation:

Complex numbers:

The most important relation that involves complex numbers is given by:


i^2 = -1

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:


ax^(2) + bx + c, a\\eq0.

This polynomial has roots
x_(1), x_(2) such that
ax^(2) + bx + c = a(x - x_(1))*(x - x_(2)), given by the following formulas:


x_(1) = (-b + √(\bigtriangleup))/(2*a)


x_(2) = (-b - √(\bigtriangleup))/(2*a)


\bigtriangleup = b^(2) - 4ac

In this question:

The solutions are:


x_1 = 1 - 3i, x_2 = 1 + 3i

We have to find the polynomial. All option have
a = 1. So


(x - (1 - 3i))(x - (1 + 3i)) = x^2 - x(1 + 3i) - x(1 - 3i) + (1 - 3i)(1 + 3i) = x^2 - x -3ix - x + 3ix + 1^2 - (3i^2) = x^2 - 2x + 1 - 9i^2 = x^2 - 2x + 1 - 9(-1) = x^2 - 2x + 10

The correct answer is given by option b.

User Ian Ross
by
6.9k points