Question

Don't understand why 4v2=-12-9 is rewritten 2v+3 and 2v+3​

Answer 1

`(2v+3)(2v + 3) = 0`

Explanation:

Given

`4v^2 = -12v - 9`

Required

How to get (2v+3) and (2v + 3) as the solution

To do this, we simply factorize the expression

`4v^2 = -12v - 9`

Move all terms to the left

`4v^2 + 12v + 9 = 0`

Split

`4v^2 + 6v + 6v + 9=0`

Expand

`2v(2v+3)+3(3v+3) = 0`

`(2v+3)(2v + 3) = 0`