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(4x-3y=14) (6x-2y=26) solve using elimination

User Anglesvar
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1 Answer

25 votes
25 votes

Answer: (2,5) or y=2 & x=5

Explanation:

1. Start off by getting the same number for either x or y by multiplying by the first number of each.

So, you would do 4(6x-2y=26) and 6(4x-3y=14) because the x's are 4x and 6x.

2. Then, you should get (24x-8y=84) & (24x-18y=84)

3. Subtract these to get 0+10y=20

4. Divide by 10 on each side to get y=2

5. Take y and plug it back into either of the original equations.

You should get (4x-3(2)=14) or (6x-2(2)=26

6. Then solve for x. (I'll be using (4x-3(2)=14) btw)

4x-3(2)=14

multiply the 2

4x-6=14

add 6 to both sides

4x=20

divide 4 to both sides

x=5

So, now you have y=2 & x=5

User Kismert
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