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What is the angle of "C" and "B" and use sins to find it

What is the angle of "C" and "B" and use sins to find it-example-1
User Ibezito
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By law of sines, all missing angles have the following measures: B = 16.201º, C = 33.849º.

How to find the missing angles by law of sines

In this problem we must find the values of missing angles of a triangle by law of sines, whose definition is shown below:


(a)/(\sin A) = (b)/(\sin B) = (c)/(\sin C)

Where:

  • a, b, c - Sides
  • A, B, C - Angles, in degrees.

If we know that a = 11, b = 4, c = 7.993 and A = 130º, then the missing angles are, respectively:


(11)/(\sin 130^\circ) = (4)/(\sin B) = (7.993)/(\sin C)

sin B = 0.279

B = 16.201º

sin C = 0.557

C = 33.849º

Angles B and C have the measures of 16.201º and 33.849º, respectively.

User RAFisherman
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